9m^2-6m-11=10

Solution for 9m^2-6m-11=10 equation:

9m^2-6m-11=10

We move all terms to the left:

9m^2-6m-11-(10)=0

We add all the numbers together, and all the variables

9m^2-6m-21=0

a = 9; b = -6; c = -21;
Δ = b2-4ac
Δ = -62-4·9·(-21)
Δ = 792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{792}=\sqrt{36*22}=\sqrt{36}*\sqrt{22}=6\sqrt{22}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{22}}{2*9}=\frac{6-6\sqrt{22}}{18}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{22}}{2*9}=\frac{6+6\sqrt{22}}{18}
$